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SOLVED:Consider a single-slit diffraction pattern. The center of the central maximum, where the intensity is I0 , is located at θ=0 . (a) Let θ and θ- be the two angles on either side of θ=0 for which I=(1)/(2) I0 . Δθ=|θ -θ-| is called the full width at half maximum, or F W H M, of the central diffraction maximum. Solve for Δθwhen the ratio between slit width a and wavelength λis (i) a / λ=2 ; (ii) a / λ=5 ; (iii) a / λ=10 . (Hint Your equation for θ or θ- cannot be solved analytically. You m
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